keno number wheel generation - math problem
$30-250 AUD
Pago na entrega
Hi I have 80 numbers (1-80) I need to pick 40 numbers in total to win. The game I am playing draws 20 out of 80 numbers and If all 20 are within my 40 numbers I win.
What I need are number groups to all but guaranteed that all 20 numbers are within 1 of my groups of 40. The best way I have thought to do this is:
*turn 80 numbers into 70 (560 numbers) 8 lines of 70 each number appears 7 times
then...
*turn those 70 numbers into 60 (420 numbers) 7 lines of 60 each number appears 6 times
then...
*turn 60 numbers into 60 (300 numbers) 6 lines of 50 each number appears 5 times
then...
*turn 50 numbers into 40 (200 numbers) 5 lines of 40 each number appears 4 times
= 1680 tickets (8x7x6x5 = 1680)
= 1680 lines of 40 numbers
Is this the best way to do it or can you please find a better way of doing it with less tickets?
I will also need the following conditions:
each line of 40 will have a total sum of 1300-1900 (sum of all numbers in set of 40)
each line of 40 will have no less than 18 odd number and no more than 22 odd numbers
each line of 40 will have no less than 18 even numbers and no more than 22 even numbers
This model I have above seems to me to be the best guarantee of getting all 40 numbers in 1 set, however I am wanting bids from people willing to work out this model and also people who can do it better (with less tickets)
I require each number set delivered to me and working out (each step).
Thanks.
ID do Projeto: #9797594
Sobre o projeto
Concedido a:
Hi Mate, Thanks for always thinking abut me for your new projects. Really enjoy puzzles and algo such as this. And thanks for very clear instructions. -ROhan
16 freelancers estão ofertando em média $117 nesse trabalho
Hi. I am very good in probability and have several similar projects done (can send the references). I am sure I will be able to do yours project. Regards
Hi. I'm a telecom engineer and I hold also a master of science in telecommunication from centrale supelec paris. I'm quite good at mathematics especially probability,statistics, theory of number, game theory etc. So Mais
Hello, I think this problem can be solved using integer programming. Have you tried this? , If you haven't, I can do this for you. Regards
Hi It seems your solution is not correct. There are C(80,20) = 3.5x10^18 twenties selected from the interval 1-80. Each forty covers C(40,20) = 137 million twenties. That means you need at least 25.6 million ( C Mais
hi i can help you in this regard. i am good in matlab programming. thanks for considering my bid.