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3 x SQL Sample Queries - 5 Star Feedback for You

Just looking for an experienced SQL developer to provide me with sample SQL queries for the following scenarios:

1) Find records where fields are special characters i.e ' @ ? ! &

2) Find records where field have an exact character count of

3) Find records which have blank fields

For a MySql database.

Just need the queries. No implementation

Estimated time required 25 minutes

5 Star feedback will be left for you

Habilidades: MySQL, SQL

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Acerca do Empregador:
( 348 comentários ) London, United Kingdom

ID do Projeto: #6797329

Premiar a:

paris2785

Hi there - My name is Paris. I've read your brief and can see that you'd like to have some queries. I have 7 years’ experience designing and developing databases and dealing with SQL queries. I am highly qualified for Mais

$8 USD / hora
(32 Avaliações)
5.7

10 freelancers estão ofertando em média $6/hora para este trabalho

kundanntl

A proposal has not yet been provided

$5 USD / hora
(15 Comentários)
4.4
niranjann08

I have the queries ready. Please come on chat so that I can share the queries Thanks, Niranjan

$8 USD / hora
(14 Comentários)
4.3
Omar112

Aucune proposition n'a encore été fournie.

$7 USD / hora
(4 Comentários)
2.6
naeemchannar

A proposal has not yet been provided

$3 USD / hora
(2 Comentários)
1.7
rkatoch

Hello, I am a .Net programmer having 8+ years of experience in Angular.js, Javascript, RESTful, Software Architecture,ASP.NET, jQuery / Prototype, Microsoft SQL Server, MVC and 100% confident to take up the task an Mais

$8 USD / hora
(0 Comentários)
0.0
gargitservices

A proposal has not yet been provided

$5 USD / hora
(1 Comentário)
0.0
rewawebdeveloper

Hello sir, I am php developer i am having good experience in mysql let me disscuss i am ready to complete your job

$5 USD / hora
(2 Comentários)
0.0
NaveenNishaan

A proposal has not yet been provided

$8 USD / hora
(0 Comentários)
0.0
bobycom

Hi, this is how it looks in MS SQL Server: select top 20 * from clients where old_addr like '%[@?!@]%' select top 20 * from clients where len(old_addr) = 20 select top 20 * from clients where (len(old_addr) = 0) o Mais

$5 USD / hora
(0 Comentários)
0.0